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Percentage Questions Set 2

Q.1. The population of a town is increased from 54500 to 58500 in one year. What is the percentage increase in the population?

  1. 6.34%
  2. 5.34%
  3. 7.34%
  4. 4.34%

Answer with Explanation:- (3)

Increase in population = 58500 - 54500 = 4000

∴ Percentage increase = (4000/54500) * 100 = 7.34 %


Q.2.  If the length of a rectangle is increased by 37.5% and its breadth is decreased by 20%, find the change in its area.

  1. 10% increase
  2. 13% decrease
  3. 15% increase
  4. 10% decrease

Answer with Explanation:- (1)

Area of rectangle = length * breadth
Length is Increased by 37.5% = 37(1/2)* 1/100 = 3/8
Breath is decreased by 20% = 1/5
l * b = Area
Old:       8 * 5 = 40
New:    11 * 4 = 44
Difference = 44-40 = 4
Original = 40
The percentage change is equal to (difference / original) * 100.
(4/40) *100 = 10% increase


Q.3. If 40% of 60% of 3/5 of a number is 504, what will be the 25% of 2/5 of that number?

  1. 350
  2. 150
  3. 175
  4. 230

Answer with Explanation:- (1)

Let the number is x.
(40/100) * (60/100) * (3/5) * x = 504
x= 3500
Now, (25/100)*(2/5)* 3500 = 350


Q.4. If a number x is 10% less than another number y and y is 10% more than 125, find the value of x.

  1. 150
  2. 125
  3. 123.75
  4. 175.25

Answer with Explanation:- (3)

We can write 10% increase as 11/10 that indicates +1 increase per 10
Similarly, we can write 10% decrease as 9/10 that indicates -1 decrease per 10
So, the required number = 125 * (11/10) * (9/10) = 123.75


Q.5. A student multiplied a number by 3/5 instead of 5/3. What is % error in calculation?

  1. 54%
  2. 64%
  3. 74%
  4. 84%

Answer with Explanation:- (3)

Let the number be x 

error = 5x/3 - 3x/5 = 16x / 15

Error % = (16x/15) * (3/5x) * 100 = 64%


Q.6. A candidate who scores 30% fails by 5 marks, while another candidate who scores 40% marks gets 10 more than minimum passing marks. The minimum marks required to pass:

  1. 50
  2. 100
  3. 45
  4. 150

Answer with Explanation:- (1)

Let the total marks = x
So, (30/100)*x +5 = (40/100)*x - 10
(3/10)*x+5 = (4/10)*x -10
3x + 50 = 4x - 100
x = 150
Marks of Candidate A= 30% of 150 = 45
Candidate A fails by 5 marks.
So, minimum passing marks = 45 + 5=50


Q.7. In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was

  1. 3100
  2. 2400
  3. 2700
  4. 3400

Answer with Explanation:- (3)

Number of valid votes = 80% of 7500 = 6000.

image Valid votes polled by other candidate = 45% of 6000 = (45/100) * 6000 = 2700


Q.8. 65% of a number is more than its 36% by 58. What is 23% of the total number?

  1. 46
  2. 23
  3. 66
  4. 58

Answer with Explanation:- (1)

The difference between 65% and 36% of the number = 29%
Also, the difference between 65% and 36% = 58
Now, 29% is equal to 58.
So, 1% = 58/29 = 2 %
Then, 100% = 200
Now, 23% of 200 = 46
Hence, the required number is 46.


Q.9. In an election 2 candidates participate, 20% of the votes are declared invalid, and the winner gets 70% of the valid votes and wins the election by 3200 votes. Find the valid votes.

  1. 10000
  2. 8000
  3. 5620
  4. 12000

Answer with Explanation:- (2)

Let total votes = 100
Then, 80 votes are valid only.
As per question, the winner gets = 80*(70/100) = 56 (valid votes),
So, the loser's votes = 80-56=24
Difference = 32, but acc to ques, it is 3200
i.e., 32 * 100 = 3200
Hence 80 * 100= 8000
So, we have to multiply 32 by 100 to make it equal to 3200.
So, 80 is also multiplied with 100.
Therefore, the total valid votes = 80 * 100= 8000


Q.10. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?

  1. 47%
  2. 57%
  3. 67%
  4. 77%

Answer with Explanation:- (2)

Total number of votes polled = (1136 + 7636 + 11628) = 20400

Required % = (11628 / 20400) * 100 = 57%


For any queries or doubts refer to comment section mentioning question number  with doubt


For more Quantitative Aptitude Topics Click here

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