Arrays : Iterating through an array using pointers

Question

Iterating through an array using pointers

Answer 1

#include <stdio.h>

#define SIZE (10)

int main()

{    

size_t i = 0;    

int *p = NULL;    

int a[SIZE];       /* Setting up the values to be i*i */    

for(i = 0; i < SIZE; ++i)    

{        

a[i] = i * i;    

}       /* Reading the values using pointers */    

for(p = a; p < a + SIZE; ++p)    

{        

printf("%d\n", *p);    

}

return 0;

}

Here, in the initialization of p in the first for loop condition, the array a decays to a pointer to its first element, as it would in almost all places where such an array variable is used.

Then, the ++p performs pointer arithmetic on the pointer p and walks one by one through the elements of the

array, and refers to them by dereferencing them with *p.