Program to implement structure time using C programming

Question

Define structure data type called time_struct containing three member’s integer hour, integer minute and integer second. Develop a program that would assign values to the individual number and display the time in the following format: 16: 40:51

Answer 1

In this program we are going to implement a structure called time_struct containing three member’s integer hour, integer minute and integer second.

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Example :

#include<stdio.h> #include<conio.h> //Declaration of structure time_struct struct time_struct{ int hour,minute,second; }time; //Member time declared void main() { int i; clrscr(); //Data input from user printf("\nEnter the time in hour, minute and second format"); scanf("%d%d%d",&time.hour,&time.minute,&time.second); //Formating of the inserted data if(time.minute>60 || time.second>60) printf("\nPlease enter valid time format"); else { printf("\nEntered Time is :"); if(time.hour<=9 && time.minute<=9 && time.second<=9) printf("\n0%d:0%d:0%d",time.hour,time.minute,time.second); else if(time.hour<=9 && time.minute>9 && time.second>9) printf("\n0%d:%d:%d",time.hour,time.minute,time.second); else if(time.hour>9 && time.minute<=9 && time.second>9) printf("\n%d:0%d:%d",time.hour,time.minute,time.second); else if(time.hour>9 && time.minute>9 && time.second<=9) printf("\n%d:%d:0%d",time.hour,time.minute,time.second); else if(time.hour<=9 && time.minute<=9 && time.second>9) printf("\n0%d:0%d:%d",time.hour,time.minute,time.second); else if(time.hour<=9 && time.minute>9 && time.second<=9) printf("\n0%d:%d:0%d",time.hour,time.minute,time.second); else if(time.hour>9 && time.minute<=9 && time.second<=9) printf("\n%d:0%d:0%d",time.hour,time.minute,time.second); else printf("\n%d:%d:%d",time.hour,time.minute,time.second); } getch(); }

Output :

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